Integrate the following w. r. t. x : (5x^2 + 20x + 6)/(x^3 + 2x^2 + x)

Question

Integrate the following w. r. t. x :

\(\frac{5x^2 + 20x + 6}{x^3 + 2x^2 + x}\)

(5x² + 20x + 6)/(x³ + 2x² + x)

Answer 1

(5x² + 20x + 6)/(x³ + 2x² + x)

Put x = 0, we get

0 + 0 + 6 = A(1) + B(0)(1) + C(0)

\(\therefore A = 6\)

Put x + 1 = 0, i.e. x = -1, we get

Put x = 1,we get