Correct option is (A) x2 – 16
Let the other zero be \(\alpha.\)
\(\therefore\) \(\alpha+4=0\)
\(\Rightarrow\) \(\alpha=-4\)
\(\therefore\) Product of zeros \(=4\alpha=4\times-4=-16\)
Required quadratic polynomial \(=x^2\) - (sum of zeros) x + product of zeros
\(=x^2-0.x+(-16)\)
\(=x^2 -16\)