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Let f(x) = {(1 - cos 4x)/x^2, if x < 0 and a, if x = 0 and x/(√(16 + √x) - 4),

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Let f(x) = {(1 - cos 4x)/x2, if x < 0 and a, if x = 0 and √x/(√(16 + √x) - 4), if x > 0}. If f(x) is continuous at x = 0, determine the value of a.

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2 Answers

+3 votes
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Best answer

Since the function is continues at x = 0

Also, f(0) = 8

Hence, a = 8.

+6 votes
by (30.7k points)

Given  that,

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