Question

`H_(3)C-underset(CH_(3))underset(|)(CH)-CH=CH_(2)+HBr to A`.
A is predominantly
A. `CH_(3)-underset(Br)underset(|)(CH)-underset(CH_(3))underset(|)(CH)-CH_(3)`
B. `CH_(3)-underset(CH_(3))underset(|)(CH)-underset(Br)underset(|)(CH)-CH_(3)`
C. `CH_(3)-underset(CH_(3))underset(|)(CH)-CH_(2)CH_(2)Br`
D. `CH_(3)-underset(CH_(3))underset(|)overset(Br)overset(|)(C)-CH_(2)CH_(3)`

Answer 1

Correct Answer - D