Question

Calculate the potential of hydrogen electrode in contact with a solution whose `pH=10`.

Answer 1

For hydrogen electrode, `H^(+)+e^(-) to 1//2H_(2)`
Applying Nernst equation.
`E_((H^(+)//1//2H_(2)))^(@)=E_((H^(+)//1//2H_(2)))^(@)-(0.0591)/(n)"log"(1)/([H^(+)])`
`=0-(0.0591)/(1)"log"(1)/((10^(-10)))" "[pH=10 , [H^(+)]=10^(-10) M]`
`=0-(0.0591)/(1)xx(10" log "10)=-0.591 V`