Question

How many moles of copper will be deposited from a solution of `CuSO_(4)` by passing 24125 C of electricity ?

Answer 1

`underset((2xx96500" C"))(Cu^(2+)(aq))+underset(1" mol")2e^(-) to Cu(s)`
`2xx96500C " of charge will deposit " Cu=1 mol`
`" Or " 24125C "of charge will deposit " Cu =(1 mol)xx((24125C))/((2xx96500C))=0.125" mol"`