Correct Answer - 0.0124 g
Current (c )=0.5 ampere, Time (t) `=40xx60=2400" s"`
Amount of charge (Q) passed`=cxxt=(0.5 "ampere")xx(2400s)=1200" C "`
`2H^(+)(aq)+underset(2xx96500C(193000C))(2e^(-)) to underset(1 mol(2g))(H_(2)(g))`
`193000" C "` of charge will evolve `H_(2)(g)=2g`
`1200" C " "of charge will evolve " H_(2)(g)=((2g)xx(1200C))/((193000C))=0.0124" g"`.
