Question

Calculate the mass of Ag deposited at cathode when a current of 2 ampere was passed through a solution for 15 minutes.

Answer 1

Correct Answer - 2.014 g
Reaction at cathode is :
`underset(1F(1xx96500" C"))(Ag^(+)(aq))+e^(-) to underset(1" mol"(108 g))(Ag(s))`
96500C of charge is required to deposit Ag=108 g.
1800 C of charge required to deposit `Ag=(108 g)xx((1800 C))/((96500C))=2.014 g`.