Question

The potential of a hydrogen electrode at pH=10 is :
A. `+0.59" V "`
B. `0.00" V"`
C. `-0.59" V "`
D. `-0.059" V "`

Answer 1

Correct Answer - C
(c ) `H^(+)+e^(-) to 1//2 H_(2)`
`E=E^(@)-(0.059)/(n)"log"(1)/([H^(+)])=-(0.059)/(1)pH`
`=(0-0.059)/(1)xx10=0-0.59=-0.59" V"`