Question

For a reaction carried at 400 K,
`NO_(2)(g) + CO_(2)(g) to CO_(2)(g) + NO_(2)(g)`, the proposed mechanism is as follows:
`NO_(2) + NO_(2) overset("Slow")to NO + NO_(3) NO_(3) + CO overset("Fast")to CO_(2) + NO_(2)`
What is the rate law for the reaction?

Answer 1

The slow step for the reaction is:
`NO_(2) + NO_(2) to NO + NO_(3)` (Slow)
The rate law equation is:
`Rate( r) = k[NO_(2)][NO_(2)]= k[NO_(2)]^(2)`.