Question

Activation energy `(E_(a))` and rate constant `(K_(1)` and `(K_(2))` for a chemical reaction at two different temperatures `T_(1)` and `T_(2)` are related by:
A. In `K_(2)/K_(1) = E_(a)/R(1/T_(1) - 1/T_(2))`
B. In `k_(2)/k_(1) = -E_(a)/R(1/T_(2)-1/T_(1))`
C. In `k_(2)/k_(1) = -E_(a)/R(1/T_(2)+1/T_(1))`
D. In `k_(2)/k_(1) = E_(a)/R(1/T_(1)-1/T_(2))`

Answer 1

Correct Answer - B::D
b,d) Both options are correct.