Correct Answer - D
d) `underset("Initial conc")(12M)overset(t_(1//2))to6Moverset(t_(1//2))tounderset("Final conc.")(3M)`
`t_(1//2) = 10`min , k = `(0.693)/(10)=0.0693 min^(-1)`
After 20 minutes, the concentration will be 3M.
rate =k[3M] = `(0.0693 min^(-1) xx 3M)`s