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`Y underset("Reduction")overset(Z)hArr R_(2) C = NH overset(H_(3)^(+)O)rarr X`
In the above sequence of reactions X, Y and Z are
A. aldehyde, ketone, `NH_(3)`
B. ketone, `1^(@)` amine, `KMnO_(4)`
C. ketone, `2^(@)` amine, `KMnO_(4)`
D. ketimine, `1^(@)` amine, `NH_(3)`

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Correct Answer - B
`underset(1^(@)" Amine (Y)")(R_(2)CHNH_(2)) underset("Reduction")overset(KMnO_(4)//H^(+))(hArr) R_(2)CH=NH overset(H_(2)O^(+))(rarr) underset("Ketone (X)")(R_(2)C=O)+NaNH_(3)`
Thus `Z` is `KMnO_(4)//H^(+)`.

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