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The compound that will react most readily NaOH to form methanol is
A. `(CH_(3))_(4)N^(+)I^(-)`
B. `CH_(3)OCH_(3)`
C. `(CH_(3))_(3)S^(+) I^(-)`
D. `(CH_(3))_(3)C Cl`.

1 Answer

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Best answer
Correct Answer - A
`(CH_(3))_(4) overset(+)(N)I^(-)+NaOH rarr NaI+(CH_(3))_(3)N+CH_(3)OH`

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