Correct option is (D) (b, a)
Given that \(\frac{x}{b}=\frac{y}{a}\)
\(\Rightarrow\) ax = by (By cross multiplication)
\(\Rightarrow\) ax - by = 0 ___________(1)
And \(bx+ay = a^2+b^2 \) ___________(2)
Put \(x=\frac{by}a\) from (1) into (2), we get
\(\frac{b^2y}a+ay=a^2+b^2\)
\(\Rightarrow\) \((b^2+a^2)y=(a^2+b^2)a\)
\(\Rightarrow y=\frac{(a^2+b^2)a}{a^2+b^2}=a\)
\(\therefore x=\frac{by}a=\frac{ba}a=b\)
Hence, (x, y) = (b, a)