Correct option is (A) (+7,-2)
The given quadratic polynomial is
\(P(x)=x^2-5x-14\)
For zeros of polynomial, we have
P(x) = 0
\(\Rightarrow x^2-5x-14=0\)
\(\Rightarrow x^2-7x+2x-14=0\)
\(\Rightarrow\) x (x - 7) + 2 (x - 7) = 0
\(\Rightarrow\) (x - 7) (x+2) = 0
\(\Rightarrow\) x - 7 = 0 or x+2 = 0
\(\Rightarrow\) x = 7 or x = -2
Hence, the zeros of the quadratic polynomial are 7 & -2.