Correct option is (D) 2 – √3
Given quadratic equation is \(x^2-4x+1=0\)
Let the other root be x.
\(\therefore\) Sum of roots \(=\frac{-(-4)}1=4\)
\(\Rightarrow\) \(x+2+\sqrt{3}=4\)
\(\Rightarrow\) \(x=4-2-\sqrt3\)
\(\Rightarrow\) x = \(2-\sqrt{3}\)
Hence, the other root is \(2-\sqrt{3}.\)