Correct Answer - D
Minimum wavelength of continuous X-ray spectrum is given by
`lambda_("min")` (in Å)`=(12375)/("E(in eV)")`
Here, E= energy of incident electron (in eV)
= energy corresponding to minimum wavelength
`implies lambda_("min")` of X-ray `implies E=80 keV=80 xx10^(3) eV`
`:. lambda_("min")` (in Å) `=12375/(80xx10^(3))~~0.155`
Also the energy of the incident electrons `(80 keV)` is more than the ionization energy of the K-shell electrons (i.e. 72.5 keV). Therefore, characteristic X-ray spectrum will also be obtained because energy of incident electron is high enough to knock out the electron from K or L-shells.