Question

When 0.1 mol `CoCl_(3)(NH_(3))_(5)` is treated with excess of `AgNO_(3)`, 0.2 mole of AgCl are obtained. The conductivity of solution will correspond to
A. `1:3` electrolyte
B. `1:2` electrolyte
C. `1:1` electrolyte
D. `3:1` electrolyte

Answer 1

Correct Answer - B
The structure of complex is `[Co(NH_(3))_(5)Cl]Cl_(2)`. The conductivity of the solution will correspond to `1:2` electrolyte.