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The mass of nucleus `._(z)X^(A)` is less than the sum of the masses of `(A-Z)` number of neutrons and `Z` number of protons in the nucleus. The energy equivalent to the corresponding mass difference is known as the binding energy of the nucleus. A heavy nucleus of mass `M` can break into two light nuclei of mass `m_(1)` and `m_(2)` only if `(m_(1)+m_(2)) lt M`. Also two light nuclei of massws `m_(3)` and `m_(4)` can undergo complete fusion and form a heavy nucleus of mass `M` 'only if `(m_(3)+m_(4)) gt M`'. The masses of some neutral atoms are given in the table below.
`|{:(._(1)^(1)H,1.007825u,._(1)^(2)H,2.014102u,),(._(1)^(3)H,3.016050u,._(2)^(4)H,4.002603u,),(._(3)^(6)Li,6.015123u,._(3)^(7)Li,7.016004u,),(._(30)^(70)Zn,69.925325u,._(34)^(82)Se,81.916709u,),(._(64)^(152)Gd,151.91980u,._(82)^(206)Pb,205.97445u,),(._(83)^(209)Bi,208.980388u,._(84)^(210)Po,209.982876u,):}|`
The correct statement is
A. The nucleus `._(3)^(6)Li` can emit an alpha particle
B. The nucleus `._(84)^(210)Po` can emit a proton
C. Deuteron and alpha particle can undergo complete fusion
D. The nuclei `._(30)^(70)Zn` and `._(34)^(82)Se` can undergo complete fusion

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Best answer
Correct Answer - C
Only in option (C), sum of masses of product is less then sum of masses of reactant
for reaction `._(1)(2)H+_(2)^(4)He rarr _(3)^(6)Li`.
As `M_(Li) lt M_("Deutron")+M_("alpha")`

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