Question

Combination between Pt(IV), `NH_3` and `Cl^(-)` results in the formation of seven complexes. One of these complexes is `[Pt(NH_3)_6]Cl_4`
(i) Write the formulae and IUPAC names of the other six complexes .
(ii) Which will have highest molar conductivity ?
(iii) Which of these is non-ionic ?
(iv) What is the the C.N of Pt in these complexes ?

Answer 1

(i) The structures and IUPAC names of other six complexes are :
(a) `[Pt(NH_3)_(5)Cl]Cl_3` : pentaammine chloridoplatinum (IV) chloride .
(b) `[Pt(NH_3)_(4)Cl_2]Cl_2` : tetraamminechloridoplatinum (IV) chloride .
(c) `[Pt(NH_3)_(5)Cl_3]Cl` : triamminetrichloridoplatinum (IV) chloride
(d) `[Pt(NH_3)CL_4]` : diamminetetrachloridoplatinum (IV) (e) `[Pt(NH_3)Cl_5]^(-)` : amminepentachloridoplatinate(IV)
(f) `[PtCl_6]^(2-)` : hexachloridoplatinare (IV)
(ii) The complex `[Pt(NH_3)_6]Cl_4` has the maximum molar conductivity as it forms maximum ion (five) in solutiion.
(iii) The compound (d) is non-ionic.
(iv) The C.N of Pt in all the complexes is 6.