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The oxidation state of `Cr` in `[Cr(NH_(3))_(4)Cl_(2)]^(+)` is:

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The oxidation state of `Cr` in `[Cr(NH_(3))_(4)Cl_(2)]^(+)` is:
A. `+2`
B. `+3`
C. `+4`
D. `+5`
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Correct Answer - A
`[Cr(NH_3)_4Cl_2]^(+)`
x + 4(0) + 2(-1) + +1
x = +1 + 2 = +3
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