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`underset(("bot"))(Cu+conc.HNO_(3))toCu(NO_(3))_(2)+X` (oxide of nitrogen) then X is:

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`underset(("bot"))(Cu+conc.HNO_(3))toCu(NO_(3))_(2)+X`
(oxide of nitrogen) then X is:
A. `N_(2)O`
B. `NO_(2)`
C. `NO`
D. `N_(2)O_(3)`
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Correct Answer - B
`2 conc. HNO_(3) to 2H_(2)O+2NO_(2)+[O]`
`Cu+2HNO_(3) to Cu(NO_(3))_(2)+2[H]`
`2[H]+[O]to2H_(2)O`
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