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The total number of `alpha` and `beta` particles emitted in the nuclear reaction `._(92)^(238)U rarr ._(82)^(214) Pb` is

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Correct Answer - 8
`._(92)^(238)Urarr._(82)^(214)Pb +x._(2)He^(4)+y ._(-1)e^(0)`
Applying mass number balance
`238=214 +4x " " x=6`
Applying nuclear charge balance
`92=82+2x-y`
`92=82+12-y`
`y=2`
Total no. of `alpha` & `beta` particle emitted=8

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