Question

A calorimeter will heat capacity equivalent to having `13.3` moles of water is used to measured the heat of combustion from `0.303 g` of sugar `(C_(12)H_(22)O_(11))`. The temperature increase was found to be `5.0 K`. Calculate the heat released, the amount of heat released by `1.0 g`, and `1.0` mole of sugar. (Molar heat capacity of water = 75.2 J/mol K)

Answer 1

Heat released, `q_(v)`,
`q_(v)=13.3xx75.2xx5.0 K`
`=5000 J`
The amount of heat released by `1.0g` would be,
`5000 J//0.303 g=16.5" kJ/g"`
since the molecular weight of sugar is 342 h/mol, the amount of hear released by `1.0` mole would be `16.5xx342=56431" kJ/mol"`.

Comments

How 75 came

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75.2 is the molar heat capacity of water.