`C_(V) (T_(2)-300)=- 1((RT_(2))/(1)-(RT_(2))/(10))`
`gamma= 1.33 =(4)/(3) = (C_(p))/(C_(v))=(4)/(3)" "C_(p)= C_(v) +R`
`3R (T_(2)-300) = -RT_(2)+(RT_(1))/(10)`
`4RT_(2) = 30R + 900 R`
`T_(2) = (930)/(4)=232.5 K`
`W= 3R(232.5 -300)`
`W =- 202.5 R =- 1.683 kJ`