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A bar magnet of magnetic moment `3.0 A-m^(2)` is placed in a uniform magnetic induction field of `2xx10^(-5)T`. If each pole of the magnet experiences a force of `6xx10^(-4)N`, the length of the magnet is

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Correct Answer - D
Force experinced by each pole bar magnet is given by
f=mB
where, m is the pole strength o f bar magnet
` " " M=mL`
`therefore " " F=(M)/(L)xxB Rightarrow 6xx10^(-4)=(3)/(L)xx2xx10^(-5)`
L=0.1m

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