Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
98 views
in Physics by (91.5k points)
closed by
An inductor (L = 100 mH), a resistor `(R = 100Omega)` and a battery (E = 100 V) are initially connected in series as shown in the figure. After a long time the battery is disconnected after short circuiting the points A and B. The current in the circuit 1 ms after the short circuit is
image
A. eA
B. 0.1A
C. 1A
D. 1/eA

1 Answer

0 votes
by (91.6k points)
selected by
 
Best answer
Correct Answer - D
During decay of current,
`i=i_(0)e^(-(Rt)/(L))=(E)/(R)e^(-(Rt)/(L))=(100)/(100)e^((100xx10^(-3))/(100xx10^(-3)))=(1)/(e)A`

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...