Correct Answer - A
`f = 2ma` ....(1)
`a_(cm) = a + alpha R` ....(2)
`tau_(0) = I_(0) alpha`
`F + f = (2)/(5) m R alpha`....(3)
`F - f - ma = ma_(cm)` .........(4)
on solving
`a_(cm) = (22 alpha R)/(25)`......(7)
`alpha = (25F)/(16 mR)`
`a = (-3F)/(16m)`
and `f = 2 ma`
`f = 2 xx m xx - (-3F)/(16m)`
`f = - (3F)/(8)`
Here -ve sign indicates that the direction is opposite.