Correct Answer - C
Given, number of turns of solenoid, N = 1000
Current, I = 4A
Magnetic flux, `phi_(B)=4xx10^(-3)Wb`
`because` Self-inductance of solenoid is given by
`L=(phi_(B)N)/(I)`
Substituting the given values in Eq. (i), we get
`L=(4xx10^(-3)xx1000)/(4)=1H`