Question

The `Th_(90)^(232)` atom has successive alpha and beta decays to the end product `Pb_(82)^(208)` . The numbers of alpha and beta. Particles. Emitted in the process respecitvely are-
A. 4,6
B. 4,4
C. 6,2
D. 6,4

Answer 1

Correct Answer - D
Mass number get charge by `rArr4xxn`
because atomic number charge occur only in `alpha`
decay
4n=232-208
4n=24
4n=6
`alpharArr4`
Mass number get charge by `rArr24`
New atomic number `rArr90-6xx2+P`
90-12+P=82
P=94-90=4
`betarArr4`