`85g of H_(2SO_(2)` are present in the solution =100g
17 g of `H_(2)SO_(4)` are present in the solution`=((100g))/((85g))xx(17g)=20g`
Thus, mass of solution= 20g , Density of solution =`1.7g cm ^(-3)`
Volume of solution =`(Mass)/(Density)=(20g)/(1.7cm^(-3))=11.8cm^(3)`