Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
95 views
in Physics by (91.5k points)
closed by
In the L-C-R circuit as shown in figure,
image
A. Current will lead the voltage
B. Runs value of current is 20 A
C. Power factor of the circuit is `1/sqrt 2`
D. Voltage drop across resistance is 200 V

1 Answer

0 votes
by (91.6k points)
selected by
 
Best answer
Correct Answer - A::B::C::D
(a,b,c,d) `X_(C)gtX_(L)`, Hence, current will lead the voltate.
`Z=sqrt(R^(2)+(X_(C)-X_(L))^(2)= 10sqrt(2)Omega`
`therefore I_(rms) = V_(rms)/Z = (400sqrt(2))/(10sqrt(2)) = 1/sqrt(2)`
`V_(R) = I_(rms)R=(20)(1)=200V`

No related questions found

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...