Question

A solution contains 20 g sodium chloride in `95cm^(3)` solution. The density of solution is 1.25 g `cm^(-3) g cm^(-3)`. What is the mass present of NaCI ?

Answer 1

Correct Answer - 0.1684
Density of NaCI solution `=1.25 g cm^(-3)`: Volume of solution = 95`cm^(3)`
`"Mass of solution" ="Volume"xx"density"=(95cm^(3))xx(1.25 g cm^(-3))=118.75 g`
`"Mass percent of NaCI" =("Mass of NaCI")/("Mass of solution")xx100=((20g))/((118.75 g))xx100=16.84%`.