Correct Answer - B
Given energy flux, `phi = 20 W//cm^(2)`
Area, `A = 30 cm^(2)`
Time, `t = 30` min = `30 xx 60 s`
Now, total energy following on the surface in time t is,
`u = phi At = 20 xx 30 xx (30 xx 60) J`
Momentum of the incident light `= U/c`
`= (20 xx 30 xx (30 xx 60))/(3 xx 10^(8)) = 36 xx 10^(-4) kg-m//s`
Momentum of the reflected light `= 0`
`:.` Momentum delivered to the surface
`= 36 xx 10^(-4) -0 = 36 xx 10^(-4) kg-m//s`