Correct option is (C) 5
Given that \(a_1+a_5=10\)
\(\Rightarrow a+(a+4d)=10,\) where d is common difference \((\because a_n=a+(n-1)d)\)
\(\Rightarrow2a+4d=10\)
\(\Rightarrow a+2d=\frac{10}2=5\)
\(\therefore a_3=5\) \((\because a_3=a+2d)\)
Hence, third term of given A.P. is 5.