Correct option is (B) 104
Given sequence is 5, 14, 23, ......
\(\therefore a_1=5,a_2=14,a_3=23\)
Now \(a_2-a_1=14-5=9,\)
\(a_3-a_2=23-5=9\)
\(\because\) \(a_2-a_1\) \(=a_3-a_2\)
\(\therefore\) Given sequence is an arithmetic progression whose first term is 5 & common difference is 9.
\(\because\) \(a_{12}=a+11d\) \((\because a_n=a+(n-1)d)\)
\(=5+11\times9\) \((\because a=a_1=5\;\&\;d=a_2-a_1=9)\)
\(=5+99=104\)
