Question

Assuming the atomic weight of a metal M to be 56, find the empirical formula of its oxide containing 70.0% of M.

Answer 1

Given :

Atomic mass of M = 56 

Percentage of M = 70.0% 

To find :

The empirical formula of the compound 

Calculation :

% M = 70.0% 

Hence,

% O = 30.0%, 

Atomic mass of O = 16 u

Hence,

The ratio of number of moles of M:O is \(\frac{1.25}{1.25}\) = 1 and \(\frac{1.875}{1.25}\) = 1.5

Convert the ratio into whole number by multiplying by the suitable coefficient, i.e., 2. 

Therefore,

The ratio of number of moles of M : O is 2 : 3. 

Hence,

The empirical formula is M₂O₃.

∴ Empirical formula of the compound = M₂O₃

Answer 2

answer is M......