Use app×
QUIZARD
QUIZARD
JEE MAIN 2026 Crash Course
NEET 2026 Crash Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
767 views
in Chemistry by (31.1k points)
closed by

Perform each of the following calculations. Round off  answers to three digits.

a. (3.26 × 104) (1.54 × 106

b. (8.39 × 107) (4.53 × 109)

c. \(\frac{8.94\times 10^6}{4.35\times 10^4}\)

d. \(\frac{(9.28\times 10^9)\times (9.9\times 10^{-7})}{(511)\times (2.98\times 10^{-6})}\)

1 Answer

+1 vote
by (30.3k points)
selected by
 
Best answer

a. (3.26 × 104) (1.54 × 106) = 5.0204 × 104+6 

= 5.02 × 1010

b. (8.39 × 107) (4.53 × 109) = 38.0067 × 107+9

= 38.0067 × 1016 

= 3.80 x 1017

c. \(\frac{8.94\times 10^6}{4.35\times 10^4}\) = 2.055 x 106-4

= 2.06 x 102

d. \(\frac{(9.28\times 10^9)\times (9.9\times 10^{-7})}{(511)\times (2.98\times 10^{-6})}\) = 0.06033 x 109-7-(-6)

= 0.06033 x 108

= 6.03 x 106

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...