There will be three different flourine-flourine distance in molecules `CF_2 (C )_2CH_2`.Assuming ideal bond angles for a particular hybridisation (assume no distortion due to double bonds) find out the smaller flourine-flourine distance and fill the result (in pm) in the increasing order in your answer sheet.Round off your answer to the nearest whole number.
(Given that C-F bond length =134 pm, C=C bond length =134 pm `sqrt3=1.73`)
