Correct Answer - B
`S_1`:It is because `Mn^(2+)` has `3d^5` configuration which has extra stability.
`S_2:`Not titanium but Copper , because with +1 oxidation state an extra stable configuration ,`3d^10` results.
`S_3`:Not stable as it undergoes disproportionation `2Cu^(+)(aq)toCu^(2+)(aq)+Cu(s)`.The `E^@` value for this is favourable.