Correct Answer - A
The region bounded by the circle and lines `x=0` and `x=2` in first quadrant is shown by shaded region in the figure.
` :. "Required area" =int_(0)^(2)ydx=int_(0)^(2)sqrt(4-x^(2))dx`
` [(x)/(2)sqrt(4-x^(2))+(4)/(2)"sin"^(-1)((x)/(2))]_(0)^(2)`
`=0+2sin^(-1)(1)-0`
`=2xx(pi)/(2)=pi` sq. units.