Correct Answer - A
Here `i = 60^(@), A = 30^(@), delta = 30^(@)`
As `i + e = A + delta`
`e = A + delta - i = 30^(@) + 30^(@) - 60^(@) - 0^(@)`
Hence emergent ray is normal to the surface.
`e = 0^(@) rArr r_(2) = 0^(@)`
As `r_(1) r_(2) = A`
`:. r_(1) = A - r_(2) = 30^(@) - 0^(@) = 30^(@)`
`mu = (sin 60^(@))/(sin 30^(@)) = (sqrt(3))/(2) xx (2)/(1) = sqrt(3) = 1.732`