Question

Two blocks of mass = 2 kg and M = 5 kg are in contact on a frictionless table. A horizonatal force F (= 35 N) is applies to m. Find the force of contact between the block, will the force of contact remain same if F is applied to M ?

Answer 1

As the bloks are rigid under the action of a force F, both will move
with same acceleration `a=(F)/(m+M)=(35)/(2+5)=5 m//s^(2)`
force of contact `f_(1)=Ma=5xx5=25N`
If the force is applied to M then its action on m will be
`f_(2)=ma=2xx5=10N`.