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An organic compound with C =40 % and H= 6.7% will have the empirical formula
A. `CH_(4)`
B. `CH_(4)O`
C. `C_(3)H_(6)O_(3)`
D. `C_(2)H_(4)O_(2)`

1 Answer

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Best answer
Correct Answer - B
Ratio of C:H:O
`=40/12:(6.7)/(1):(53.33)/(16)=1:2:1`
Hence Empirical formula `=CH_O`

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