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In Victor Meyers method, 0.2 g of an organic substance displaced 56 mL of air at STP.The molecular mass of the compound is
A. 56
B. 112
C. 80
D. 28

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Correct Answer - C
56 mL of the vapour of O.C (displaced 56 mL air) weigh=0.2 g `therefore` 22400 mL vapour of O.C (displaced 56 mL air) weigh `=(0.2)/(56) xx 22400=80 g `

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