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An ice box used for keeping eatables cool has a total wall area of `1m^2` and a wall thichness of 5.0 cm. The thermal cunductivity of the ice box is `K=0.01 J//m^@C`. It is filled with large amount of ice at `0^@C` along with eatables on a dfay when the temperature is `30^@C` The latent heat of fusion of ice is `334xx10^3 J//kg`. The amount of ice melted in one day is ( 1 day`=86,000s`)

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` (dQ)/(dt)= (KA)/(L) "d"theta = (0.01xx1)/(0.05)xx 30=6 "joule"//s`
So `(dQ)/(dt) xx86400=6xx86400`
`Q= mL(L-"latent heat"), m=(Q)/(L)= (6xx86400)/(334xx10^(3)) =1.552"kg"`

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