Question

The electric field of an electromagnetic wave travelling through vaccum is given by the equation ` E = E_(0) "sin"(kx - omegat)` The quantity that is independent of wavelength is
A. `komega`
B. `(k)/(omega)`
C. `k^(2)omega`
D. `omega`

Answer 1

Correct Answer - B
Here, `k=(2pi)/(lambda),omega=2piupsilon`
`therefore" "(k)/(omega)=(2pi//lambda)/(2piupsilon)=(1)/(upsilon lambda)=(1)/(c)" "(thereforec=ulambda)`
where c is the speed of electromagnetic wave in vacuum.
It is a constant whose value is `3xx10^(8)"m s"^(-1)`.