Correct Answer - A
Energy incident =`IpiR^(2) = 912 xx piR^(2)`
Energy emitted , assuming temp of the sphere at steady state to be `T,`
`sigma xx 4pi R^(2)(T^(4) - 300^(4))`
At quilibrium, `sigma xx 4pi R^(2)(T^(4) - 300^(4)) = 912 xx piR^(2)`
`implies T^(4) - 300^(4) = (912)/(5.7 xx 10^(-8) xx 4) = 40 xx 10^(8)`
`therefore T^(4) = (40+81) xx 10^(8)`
`therefore T = 331.66 approx 330K`