Question

A transistor connected in common emitter mode, the voltage drop across the collector is 2 V and `beta` is 50, the base current if `R_C` is `2 kOmega` is
A. `40 muA`
B. `20 muA`
C. `30 muA`
D. `15 muA`

Answer 1

Correct Answer - B
Using, `I_C=(V_(CE))/R_C=2/(2xx10^3)=10^(-3)`=1 mA
`therefore beta=I_C/I_B,I_B=I_C/beta=10^(-3)/50A=20 muA`